December 23, 2012

TIPS TO IDENTIFY ORGANIC COMPOUNDS

Some Guidelines to Solve Organic Problems
To learn organic chemistry in detail there is no better way than doing lots of problems. Do as many problems as you can, as regularly as you can and shortly you will be able to do them in your head.
After that you will be familiar with the organic chemistry.
The organic problems originate from many sources like books, examinations, one’s own creation, etc.,
  1. Alter the Text question into a Flow chart;
  2. Normally it is good decision to start where much information appears;
  3. Always use Structural formula;
  4. Always count the atoms to avoid a silly mistake;
  5. Do not commit immediately to a conclusion on the structures;
  6. Do not judge the answer until you have solved the problem or until you really have finished all possible trials;
Some of the problems purposely use reactions that are not in the scheme. There is always enough information provided to bring them into the scheme.
Generally Question No. 70(a) and 70(c) is from
a. Hydroxy derivatives linked with Carbonyl compounds and Carboxylic acids.
b. Carbonyl compounds linked with Carboxylic acids and Organic nitrogen compounds. 
1. FROM HYDROXY DERIVATIVES
1. Ethyl alcohol –M.F– C2H6O                                              [CH3CH2 – OH]
Primary alcohol,
Liberates H2 with Sodium metal,
No turbidity with anhydrous ZnCl2/Conc.HCl in Lucas test,
gives Red colour in Victor Meyer’s test,
undergoes Iodoform test, etc.,

2. iso-Propyl alcohol –M.F– C3H8O                                       [(CH3)2CH – OH]
Secondary alcohol,
Liberates H2 with Sodium metal,
gives turbidity within 5–10 minutes with anhydrous ZnCl2/Conc.HCl in Lucas test,
gives Blue colour in Victor Meyer’s test,
undergoes Iodoform test, etc.,

3. tert-Butyl alcohol –M.F– C4H10O                                     [(CH3)3C – OH]
Tertiary alcohol,
Liberates H2 with Sodium metal,
isomeric with n-Butyl alcohol and sec-Butyl alcohol,
forms turbidity immediately with anhydrous ZnCl2/Conc.HCl in Lucas test,
undergoes only dehydration with Cu to give alkene / olefin (Isobutylene),
No reaction with Nitrous acid in Victor Meyer’s test (Colourless solution), etc.,

4. Ethylene glycolM.F–C2H6O2                                 [OH – CH2 – CH2 – OH]
Dihydric alcohol,
Liberates H2 with Sodium metal,
with anhydrous ZnCl2 gives Acetaldehyde,
with conc. H3PO4 gives Diethylene glycol,
gives Terylene with Terephthalic acid,
with conc H2SO4 gives Dioxan,
on oxidation with acidified K2Cr2O7 / KMnO4 gives Formic acid,
used as coolant in aeroplane engines, etc.,

5. Glycerol–M.F– C3H8O3                                        [OH – CH2 – CH (OH) – CH2 – OH]
Trihydric alcohol,
obtained from soap and candle industry,
used in copying inks and stamp pad inks, etc.,

6. Benzyl alcoholM.F– C7H8O                                              [C6H5 – CH2 – OH]
Arylated aliphatic alcohol,
obtained from Cannizzaro reaction,
with CH3COOH in the presence of conc. H2SO4 gives Benzyl acetate which has the fragrance of jasmine,
Antiseptic in ointments, etc.,

7. Phenol –M.F– C6H6O                                                         [C6H5 – OH]
Carbolic acid odour,
prepared from Cumene,
gives violet colour with neutral FeCl3,
with Bromine water gives white precipitate,
answers Dye test / Coupling reaction,
with CHCl3 and NaOH gives two isomers – o-Hydroxy benzaldehyde / Salicylaldehyde and p-Hydroxy benzaldehyde (Riemer-Tiemann reaction),
with CCl4 and NaOH gives two isomers – o-Hydroxy benzoic acid / Salicyclic acid and p-Hydroxy benzoic acid,
with CO2 and alkali gives o-Hydroxy benzoic acid / Salicylic acid (Kolbe’s reaction),
with HCHO and NaOH it condenses to give p- Hydroxy phenyl methanol,
 used to prepare Bakelite, Phenolphthalein, Picric acid, etc.,
2. FROM CARBONYL COMPOUNDS
1. Acetaldehyde–M.F– C2H4O                                              [CH3 – CHO]
Undergoes Aldol Condensation,
undergoes Addition reaction with bisulphite, hydrazine, phenyl hydrazine, semicarbazide, hydrogen cyanide, hydroxylamine, etc.,
gives Aldimine on reaction with ammonia,
undergoes Clemmenson reduction with Zinc amalgam and con.HCl,
undergoes Wolf-Kishner reduction with Hydrazine and Sodium ethoxide,
reduces both Tollen’s reagent and Fehling’s solution,
gives pink colour with Schiff’s reagent,
gives Secondary alcohol with Grignard addition,
 with Conc.H2SO4 undergoes polymerization to give Paraldehyde, a cyclic compound, etc.,

2. Formaldehyde –M.F– CH2O                                              [HCHO]
Undergoes Cannizzaro reaction,
undergoes Addition reaction with bisulphite, hydrazine, phenyl hydrazine, semicarbazide, hydrogen cyanide, hydroxylamine, etc.,
gives Urotropine on reaction with ammonia,
undergoes Clemmenson reduction with Zinc amalgam and con.HCl,
undergoes Wolf-Kishner reduction with Hydrazine and Sodium ethoxide,
reduces both Tollen’s reagent and Fehling’s  solution,
gives Primary alcohol with Grignard addition,
used in biological specimens, etc.,

3. Acetone–M.F–C3H6O                                                         [CH3 – CO – CH3]
Undergoes Aldol Condensation,
undergoes Addition reaction with bisulphite, hydrazine, phenyl hydrazine, semicarbazide, hydrogen cyanide, hydroxylamine, etc.,
gives Diacetone amine on reaction with ammonia,
undergoes Clemmenson reduction with Zinc amalgam and con.HCl,
undergoes Wolf-Kishner reduction with Hydrazine and Sodium ethoxide,
on oxidation gives acid having lesser number of  carbon atom compared to acetone,
does not reduce Tollen’s reagent and Fehling’s solution,
answers Iodoform test,
gives Tertiary alcohol with Grignard addition,
with dry HCl gives Mesityl oxide (C6H10O) and then Phorone (C9H14O),
in the presence of conc.H2SO4 condenses to give Mesitylene / 1, 3, 5-Trimethyl benzene (C9H12),
used in the manufacture of Cordite,
used in the preparation of Sulphonal, etc.,

4. Benzaldehyde–M.F– C7H6O                                              [C6H5 – CHO]
Has Smell of bitter almond and known as Oil of bitter almonds,
Undergoes Cannizaro reaction,
reduces Tollen’s reagent only,
Does not reduce Fehling’s solution, 
gives pink colour with Schiff’s reagent,
undergoes Addition reaction,
gives Hydro benzamide on reaction with ammonia,
undergoes Clemmenson reduction with Zinc amalgam and con.HCl to give Toluene (C7H8),
undergoes Wolf-Kishner reduction with Hydrazine and Sodium ethoxide to give Toluene (C7H8),
gives Schiff’s base with Pimary amines,
with Aniline gives Benzanilide,
with Cl2 in the absence of a catalyst gives Benzoyl chloride (C7H5OCl),
with Cl2 in the presence of a catalyst gives m-Chlorobenzaldehyde (C7H5OCl),
oxidized by alkaline KMnO4 to give Benzoic acid (C7H6O2),
with aqueous alcoholic KCN gives Benzoin (C14H12O2) [Benzoin Condensation],
with Acetic anhydride in the presence of Sodium acetate gives Cinnamic acid (C9H8O2) which is an aromatic unsaturated acid [Perkin’s reaction], etc.,

5. Salicylaldhyde  / o–Hydroxy benzaldehyde –M.F–C7H6O2    [o- HO – C6H4 – CHO]
Obtained from Riemer-Tiemann reaction, etc.,

6. AcetophenoneM.F– C8H8O                                                        [C6H5 – CO – CH3]
Prepared by Friedel-Craft’s acetylation and Dry distillation of Calcium benzoate and Calcium acetate,
undergoes reduction to give Phenyl methyl carbynol,
undergoes Haloform reaction,
used as hypnotic (Hypnone), etc.,

7. Benzophenone –M.F– C13H10O                                        [C6H5 – CO – C6H5]
Prepared by Friedel-Craft’s benzoylation and Dry distillation of Calcium benzoate,
undergoes reduction to give Diphenyl carbynol (Benzhydrol),
used in perfumery and preparation of benzhydrol drop, etc.,
3. FROM CARBOXYLIC ACID
1. Acetic acid –M.F–C2H4O2                                                  [CH3 – COOH]
Does not reduce Tollen’s reagent and Fehling’s solution,
 gives effervescence with the liberation of CO2 with carbonates,
gives Ester (Fruity odour) with alcohols, etc.,

2. Formic acid –M.F–CH2O2                                                  [HCOOH]
Reduces both Tollen’s reagent and Fehling’s solution, etc.,

3. Lactic acid –M.F–C3H6O3                                                 [CH3 – CH OH– CH3]
Undergoes Haloform reaction,
gives Pyruvic acid with Fenton’s reagent,
on heating gives Lactide,
used in tanning industry,
Optically active, etc.,

4. Oxalic acid M.F–C2H2O4                                                  [HOOC–COOH]
Dicarboxylic acid,
used for removing ink stains and iron stains, etc.,

5. Succinic acid / Butanedioic acid M.F– C4H6O4             [HOOC– CH2 – CH2 – COOH]
Dicarboxylic acid,
used in the manufacture of lacquers and dyes, etc.,

6. Benzoic acid–M.F– C7H6O2                                                [C6H5 – COOH]
The simplest of aromatic acids,
Prepared by side chain oxidation of benzene derivatives, 
with Soda lime gives benzene, 
Undergoes oxidation, reduction,
Undergoes electrophilic substitution at meta-position,
used in urinary antiseptic, etc.,

7. Salicylic acid / o-Hydroxy benzoic acid–M.F–C7H6O3     [o- HO – C6H4 – COOH]
Obtained from Kolbe’s reaction,
with bromine water gives white precipitate,
gives violet colour with  neutral Ferric chloride,
with acetic anhydride gives Aspirin which is used as an analgesic and antipyretic,
with alcohol gives pleasant smelling liquid-Methyl salicylate which is present in Oil of winter green,
used as antiseptic and disinfectant, etc.,

8. Methylacetate–M.F–C3H6O2                                            [CH3COOCH3]
Undergoes Claisen ester condensation, etc.,

9. Acetamide–M.F–C2H5NO                                                  [CH3CONH2]
Undergoes Hoffmann’s reaction,
used in soldering flux and plasticizer in cloth, etc.,

10. Acetyl chloride–M.F–C2H3OCl                                        [CH3COCl]
Undergoes Rosenmund reduction with Pd/BaSO4, etc.,
4. FROM ORGANIC NITROGEN COMPOUNDS
1. Nitrobenzene                                                                        [C6H5 – NO2]
Has Smell of bitter almonds and called as Oil of mirbane,
undergoes reduction,
undergoes electrophilic substitution at meta-position,
used to prepare TNT, etc.,

2. Aniline –M.F–C6H7N                                                           [C6H5 – NH2]
Has fishy odour,
turns brown on exposure to air,
undergoes Carbylamine reaction,
gives Schiff’s base / Aldimine with aldehydes,
with Benzoyl chloride in the presence of NaOH gives Benzanilide (Schotten- Baumann reaction), 
gives Benzene diazonium chloride with Nitrous acid [NaNO2 / HCl] (Diazotization),
used in Sulpha drugs, etc.,

3. Benzene diazonium chloride                                                        [C6H5 – N2+Cl-]
In dry condition it is quite unstable and decomposes violently,

9 comments:

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  2. Thank you sir for guiding us to feel chemistry,an easier subject.May I get some practice problems for answering 70 a &70 c.

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  5. Thanks a lot very useful. Sir

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    1. Thank you for your Feedback / Appreciation. Best Wishes for your Success in All the Examinations.

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